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9p^2-3p-42=0
a = 9; b = -3; c = -42;
Δ = b2-4ac
Δ = -32-4·9·(-42)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-39}{2*9}=\frac{-36}{18} =-2 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+39}{2*9}=\frac{42}{18} =2+1/3 $
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